Use differentials to approximate the volume of material needed to make a rubber ball if the
radius of the hollow inner core is 2 ππ., and the thickness of the rubber is 1
8
ππ.
Volume of the sphere is V=43Οr3V=\frac{4}{3}\pi r^3V=34βΟr3
dV=43Ο(3r2)drdV=\frac{4}{3}\pi (3r^2)drdV=34βΟ(3r2)dr
=4Οr2dr=4Ο(4)2(0.2)=12.8Ο=4 \pi r^2dr\\=4\pi (4)^2(0.2)=12.8 \pi=4Οr2dr=4Ο(4)2(0.2)=12.8Ο
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