Find dy.
3. sin(xy) = x ^ 2 - y
sin(xy)=x2−yDifferentiating implicitly, we haveycos(xy)+xcos(xy)dydx=2x−dydxCollecting like terms, we have dydx(xcos(xy)+1)=2x−ycos(xy) ⟹ dydx=2x−ycos(xy)xcos(xy)+1\displaystyle \sin(xy)=x^2 -y\\ \text{Differentiating implicitly, we have}\\ y\cos(xy)+x\cos(xy)\frac{dy}{dx}= 2x-\frac{dy}{dx}\\ \text{Collecting like terms, we have }\\ \frac{dy}{dx}(x\cos(xy)+1)= 2x-y\cos(xy)\\ \implies \frac{dy}{dx} = \frac{2x-y\cos(xy)}{x\cos(xy)+1}sin(xy)=x2−yDifferentiating implicitly, we haveycos(xy)+xcos(xy)dxdy=2x−dxdyCollecting like terms, we have dxdy(xcos(xy)+1)=2x−ycos(xy)⟹dxdy=xcos(xy)+12x−ycos(xy)
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