Question #269320

Find dy.



3. sin(xy) = x ^ 2 - y

1
Expert's answer
2021-11-26T00:02:25-0500

sin(xy)=x2yDifferentiating implicitly, we haveycos(xy)+xcos(xy)dydx=2xdydxCollecting like terms, we have dydx(xcos(xy)+1)=2xycos(xy)    dydx=2xycos(xy)xcos(xy)+1\displaystyle \sin(xy)=x^2 -y\\ \text{Differentiating implicitly, we have}\\ y\cos(xy)+x\cos(xy)\frac{dy}{dx}= 2x-\frac{dy}{dx}\\ \text{Collecting like terms, we have }\\ \frac{dy}{dx}(x\cos(xy)+1)= 2x-y\cos(xy)\\ \implies \frac{dy}{dx} = \frac{2x-y\cos(xy)}{x\cos(xy)+1}


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