A stone is dropped into a pool of water. The radius of the circular ripple formed increases at 4 𝑚/𝑠. Calculate the rate at which the area of the ripple is increasing when the radius is 6m.
drdt=4m/s\frac{dr}{dt}=4m/sdtdr=4m/s
A=πr2=>dAdr=2πrA=πr²=>\frac{dA}{dr}=2πrA=πr2=>drdA=2πr
dAdt=dAdr•drdt\frac{dA}{dt}=\frac{dA}{dr}•\frac{dr}{dt}dtdA=drdA•dtdr
=>dAdt=2πr•4=8πrm2/s=>\frac{dA}{dt}=2πr•4=8πrm²/s=>dtdA=2πr•4=8πrm2/s
when r=6mr=6mr=6m
dAdt=8π(6)=48πm2/s\frac{dA}{dt}=8π(6)=48πm²/sdtdA=8π(6)=48πm2/s
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