Question #268655

A stone is dropped into a pool of water. The radius of the circular ripple formed increases at 4 𝑚/𝑠. Calculate the rate at which the area of the ripple is increasing when the radius is 6m.


1
Expert's answer
2021-11-21T17:33:24-0500

drdt=4m/s\frac{dr}{dt}=4m/s


A=πr2=>dAdr=2πrA=πr²=>\frac{dA}{dr}=2πr


dAdt=dAdrdrdt\frac{dA}{dt}=\frac{dA}{dr}•\frac{dr}{dt}


=>dAdt=2πr4=8πrm2/s=>\frac{dA}{dt}=2πr•4=8πrm²/s


when r=6mr=6m


dAdt=8π(6)=48πm2/s\frac{dA}{dt}=8π(6)=48πm²/s



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