f(x)=x4+5x3+10x2+20x+24
f(−2)=(−2)4+5(−2)3+10(−2)2+20(−2)+24
=16−40+40−40+24=0 Then the term (x+2) is a factor of the polynomial.
f(x)=x4+5x3+10x2+20x+24
f(x)=x4+2x3+3x3+6x2+4x2+8x+12x+24
=x3(x+2)+3x2(x+2)+4x(x+2)+12(x+2)
=(x+2)(x3+3x2+4x+12) Therefore the term (x+2) is a factor of the polynomial.
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