(1) If the total cost of a firm is c(x) = 1.5x^3 - 5x^2 + 20x + 5 . Find the marginal cost (in dollars) when 25 units are produced and sold. Where did you get the 3?
Given cost of firm is C(x)=1.5x3−5x2+20x+5C(x)=1.5 x^{3}-5 x^{2}+20 x+5C(x)=1.5x3−5x2+20x+5
Marginal cost =M.C=dCdx⇒M.C.=ddx(1.5x3−5x2+20x+5)=3×1.5x2−10x+20=4.5x2−10x+20 Now M.C. ∣x=25=4.5(25)2−10×25+20=4.5×625−250+20=2812.5−250+20= 2582.5\begin{aligned} \text { Marginal cost }=M . C &=\frac{d C}{d x} \\ \Rightarrow M . C . &=\frac{d}{d x}\left(1.5 x^{3}-5 x^{2}+20 x+5\right) \\ &=3 \times 1.5 x^{2}-10 x+20 \\ &=4.5 x^{2}-10 x+20 \\ \text { Now M.C. } \mid x=25 &=4.5(25)^{2}-10 \times 25+20 \\ &=4.5 \times 625-250+20 \\ &=2812.5-250+20 \\ &=\ 2582.5 \end{aligned} Marginal cost =M.C⇒M.C. Now M.C. ∣x=25=dxdC=dxd(1.5x3−5x2+20x+5)=3×1.5x2−10x+20=4.5x2−10x+20=4.5(25)2−10×25+20=4.5×625−250+20=2812.5−250+20= 2582.5
About 3:
See rules of differentiation
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