Let us list the critical points of the following function in increasing order:
f(θ)=18cos(θ)+9sin2(θ), −π≤θ≤π.
Since f′(θ)=−18sin(θ)+18sin(θ)cos(θ)=18sin(θ)(−1+cos(θ)), we conclude that f′(θ)=0 implies sin(θ)=0 or cos(θ)=1. It follows that θ=πn,n∈Z or θ=2πm,m∈Z.
Taking into account that −π≤θ≤π, we conclude that the critical points are −π, 0, π.
Answer: −π, 0, π
Comments