Question #261495

X^3-2y^3+xy(2x-y)+y(x-y)+1=0


1
Expert's answer
2021-11-08T06:11:38-0500

Incomplete question:

No information is given that what needs to done here.

Let us solve for the derivative w.r.t xx :

Let f(x,y)=x32y3+xy(2xy)+y(xy)+1f(x,y)=x^3-2y^3+xy(2x-y)+y(x-y)+1\\

=x32y3+2x2yxy2+xyy2+1=x^3-2y^3+2x^2y-xy^2+xy-y^2+1

fx=dx[x32y3+2x2yxy2+xyy2+1]=3x2+4xyy2+yf_x=\frac{\partial}{dx}[x^3-2y^3+2x^2y-xy^2+xy-y^2+1] \\ =3x^2+4xy-y^2+y





Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS