Question #261495

X^3-2y^3+xy(2x-y)+y(x-y)+1=0


Expert's answer

Incomplete question:

No information is given that what needs to done here.

Let us solve for the derivative w.r.t xx :

Let f(x,y)=x3−2y3+xy(2x−y)+y(x−y)+1f(x,y)=x^3-2y^3+xy(2x-y)+y(x-y)+1\\

=x3−2y3+2x2y−xy2+xy−y2+1=x^3-2y^3+2x^2y-xy^2+xy-y^2+1

fx=∂dx[x3−2y3+2x2y−xy2+xy−y2+1]=3x2+4xy−y2+yf_x=\frac{\partial}{dx}[x^3-2y^3+2x^2y-xy^2+xy-y^2+1] \\ =3x^2+4xy-y^2+y





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