decide whether the function is even, odd, or
neither.
f(x) = x^4+ 3
Taking into account that the domain R\RR of the function f(x)=x4+3f(x) = x^4+ 3f(x)=x4+3 is symmetric about the yyy-axis and f(−x)=(−x)4+3=x4+3=f(x),f(-x) = (-x)^4+ 3 = x^4+ 3=f(x),f(−x)=(−x)4+3=x4+3=f(x), we conclude that this function is even.
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