Question #261148

Q.6(b) A company estimates that the demand for its product fluctuates with the



price it charges. The demand function is (05 Marks)



q= 280,000 – 400p



Where q equal the number of units demanded and p equals the price in dollars.



The cost of producing q units of the product is estimated by the function



C = 350,000 + 300q + 0.0015q2



i. Determine the number of units that should be produce in order to



maximize the annual profit.



ii. What price should be charged?



iii. What is the annual profit expected to equal?

1
Expert's answer
2021-11-08T16:56:26-0500
Profit=RevenueCostProfit=Revenue-Costq=100000200p=>p(q)=5000.005qq = 100000 - 200p=>p(q)=500-0.005qR(q)=p(q)q=500q0.005q2R(q)=p(q)\cdot q=500q-0.005q^2P(q)=R(q)C(q)=P(q)=R(q)-C(q)==500q0.005q2(150000+100q+0.003q2)==500q-0.005q^2-(150000 + 100q + 0.003q^2)==400q0.008q2150000=400q-0.008q^2-150000

a.

P(q)=4000.016qP'(q)=400-0.016q

Find the critical number(s)

P(q)=0=>4000.016q=0=>q=25000P'(q)=0=>400-0.016q=0=>q=25000

P(q)=0.016<0P''(q)=-0.016<0

The function P(q)P(q) has a local maximum at q=25000.q=25000.

Since the function P(q)P(q) has the only extremum, then the function P(q)P(q) has the absolute maximum at q=25000.q=25000.

A company has to produce q=25000q=25000 units in order to maximize annual profit.


b.


p(25000)=5000.005(25000)=375p(25000)=500-0.005(25000)=375

The price is Rs375.

c.



P(25000)=400(25000)0.008(25000)2150000=P(25000)=400(25000)-0.008(25000)^2-150000==4850000=4850000

The expected annual profit is Rs4,850,000.


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