f(x)βx2+8xβ14=β(x2β8x+16)+2
=β(xβ4)2+2The function f(x)=βx2+8xβ14,xβ€4 is one-to-one. Then it has inverse.
Replace f(x) with y
y=β(xβ4)2+2,xβ€4,yβ€2 Replace every x with a y and replace every y with an x
x=β(yβ4)2+2,xβ€2,yβ€4 Solve for y
(yβ4)2=2βx,xβ€2,yβ€4
yβ4=β2βxβ
y=4β2βxβ Replace y with fβ1(x)
fβ1(x)=4β2βxβ Domain (ββ,2]