Answer to Question #258999 in Calculus for Pankaj

Question #258999



Find the following limits:



lim x approches 2 for x^2 + 4x -1/ x^2 -2x

1
Expert's answer
2021-11-03T17:13:58-0400

limx2x2+4x1x22x=?\lim\limits_{x\rarr 2}\frac{x^2+4x-1}{x^2-2x}=?

limx2x2+4x1x22x=(2)2+4(2)1222(2)\lim\limits_{x\rarr 2}\frac{x^2+4x-1}{x^2-2x}=\frac{(2)^2+4(2)-1}{2^2-2(2)}

=4+8144=\frac{4+8-1}{4-4}

=110=\frac{11}{0}

==\infty

limx2x2+4x1x22x=\therefore \lim\limits_{x\rarr 2}\frac{x^2+4x-1}{x^2-2x}=\infty


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