Question #258913

Is the function 𝑓:𝑹 →R defined as f:(x) = (x — 7) (x^3 + 11)is an odd function.

1
Expert's answer
2021-11-01T13:28:37-0400

f(x)=(x7)(x3+11)f(x)=(x7)[(x)3+11)]=(x+7)(x3+11)=(x+7)(11x3)f(x)f(x) = (x - 7) (x^3 + 11) \\f(-x) = (-x-7)[(-x)^3+11)] \\=-(x+7)(-x^3+11) \\=-(x+7)(11-x^3)\neq-f(x)

For f(x)f(x) to be an odd function: f(x)=f(x)f(-x)=-f(x)

But, there is no relation between f(x)f(x) and f(x)f(-x) here in this problem.

So, f(x)f(x) is not an odd function.


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