Answer to Question #258551 in Calculus for Olivia

Question #258551

y'' of y = x^-2 at x=2

Expert's answer

Let us find "y''" of "y = x^{-2}" at "x=2."

It follows that "y'=-2x^{-3},\\ y''=(-3)(-2)x^{-4}=6x^{-4}."

Consequently, "y''(2)=6\\cdot 2^{-4}=\\frac{6}{2^4}=\\frac{3}{2^3}=\\frac{3}8."

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