.A geometric series with first term 3 converges to the sum of 2. Find the common ratio of the series.
let a=3a=3a=3 be the 1st term and r be the common ratio ,so:
S∞=a/(1−r)S\infin=a/(1-r)S∞=a/(1−r)
S∞=3/(1−r)S\infin=3/(1-r)S∞=3/(1−r)
S∞=2S\infin=2S∞=2 ∴\therefore∴
2=3/(1−r)2=3/(1-r)2=3/(1−r)
multiply both sides by (1−r)(1-r)(1−r)
2(1−r)=32(1-r)=32(1−r)=3
2−2r=32-2r=32−2r=3
−2r=1-2r=1−2r=1
∴\therefore∴ r=−0.5r=-0.5r=−0.5 is the correct answer.
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