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Question #257390
(i) Calculate divergence A = x²zî - 2y³z²ĵ+ xy²zk at the point (1,-1,1).
Expert's answer
∂
A
x
∂
x
=
2
x
z
,
∂
A
y
∂
y
=
−
6
y
2
z
2
,
∂
A
z
∂
z
=
x
y
2
\dfrac{\partial A_x}{\partial x}=2xz, \dfrac{\partial A_y}{\partial y}=-6y^2z^2,\dfrac{\partial A_z}{\partial z}=xy^2
∂
x
∂
A
x
=
2
x
z
,
∂
y
∂
A
y
=
−
6
y
2
z
2
,
∂
z
∂
A
z
=
x
y
2
d
i
v
A
=
2
x
z
−
6
y
2
z
2
+
x
y
2
divA=2xz-6y^2z^2+xy^2
d
i
v
A
=
2
x
z
−
6
y
2
z
2
+
x
y
2
d
i
v
A
∣
(
1
,
−
1
,
1
)
=
2
(
1
)
(
1
)
−
6
(
−
1
)
2
(
1
)
2
+
1
(
−
1
)
2
divA|_{(1,-1,1)}=2(1)(1)-6(-1)^2(1)^2+1(-1)^2
d
i
v
A
∣
(
1
,
−
1
,
1
)
=
2
(
1
)
(
1
)
−
6
(
−
1
)
2
(
1
)
2
+
1
(
−
1
)
2
=
−
3
=-3
=
−
3
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