Second order derivative of (log x-x) is
as
logxx = 1
So
d2dx2(logxx)=ddx[ddx(logxx)]\cfrac{d^2}{dx^2} ( log_x x)= \cfrac{d}{dx}[\cfrac{d}{dx} (log_x x)]dx2d2(logxx)=dxd[dxd(logxx)]
Also,
ddx[ddx(logxx)]=ddx[ddx(1)]=0\cfrac{d}{dx}[\cfrac{d}{dx} (log_x x)]= \cfrac{d}{dx}[\cfrac{d}{dx} ( 1)] = 0dxd[dxd(logxx)]=dxd[dxd(1)]=0
And hence the answer is 0
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