Area enclosed =ย "\\int^1_0 \\sqrt{x}. dx-\\int^1_0 x.dx\\\\"
"=[\\frac{x^{\\frac{3}{2}}}{\\frac{3}{2}}-\\frac{x^2}{2}]^1_0\\\\\n=[\\frac{2}{3}-\\frac{1}{2}]-[0-0]\\\\\n=\\frac{1}{6}\\\\"
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