Answer to Question #249198 in Calculus for moe

Question #249198

Find the partial derivative "\\displaystyle{\\frac{\\partial z}{\\partial y}}" of the function "\\displaystyle{z^{2}=x^2+y}"


1
Expert's answer
2021-10-12T06:21:06-0400

"(z^{2})'{\\scriptscriptstyle y} = (x^{2}+y)'{\\scriptscriptstyle y}"

"2zz'{\\scriptscriptstyle y} = 1"

"{\\frac {\u2202z} {\u2202y}}=z'{\\scriptscriptstyle y}= {\\frac 1 {2z}}"


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