Consider the given right triangle with legs of length x cm. and y cm. and angle θ radians. If x is decreasing at the rate of 3 cm/min. and y is increasing at the rate of 4 cm/min., at what rate is angle θ changing when x=5 cm. and y=2 cm. ?
"y=xtan\\theta"
"\\theta=tan^{-1}(y\/x)"
"\\frac{d\\theta}{dt}=\\frac{1}{1+(y\/x)^2}\\cdot \\frac{y'x-x'y}{x^2}=\\frac{1}{1+(2\/5)^2}\\cdot \\frac{4\\cdot 5-3\\cdot 2}{5^2}=\\frac{14}{29}"
Comments
Leave a comment