Graph each function. Then identify the vertex, two points, domain, and range.
f(x) = |-1/5(x + 5)| + 2
Solution:
The graph of f(x)=∣−(x + 5)5∣ + 2f(x)=|-\frac{\left(x\:+\:5\right)}{5}|\:+\:2f(x)=∣−5(x+5)∣+2 is
From the graph:
Domain of ∣x+5∣5+2 :[Solution: −∞ <x<∞ Interval Notation: (−∞ , ∞ )]\mathrm{Domain\:of\:}\:\frac{\left|x+5\right|}{5}+2\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:<x<\infty \\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:\infty \:\right)\end{bmatrix}Domainof5∣x+5∣+2:[Solution:IntervalNotation:−∞<x<∞(−∞,∞)]
Range of ∣x+5∣5+2:[Solution: f(x)≥ 2 Interval Notation: [2, ∞ )]\mathrm{Range\:of\:}\frac{\left|x+5\right|}{5}+2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:2\:\\ \:\mathrm{Interval\:Notation:}&\:[2,\:\infty \:)\end{bmatrix}Rangeof5∣x+5∣+2:[Solution:IntervalNotation:f(x)≥2[2,∞)]
Vertex :(−5,2): (-5,2):(−5,2)
Two points :(0,3),(5,4):(0,3),(5,4):(0,3),(5,4)
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