Question #244116

Integrate ∫dy/(y(y^2 + 1))


1
Expert's answer
2021-09-30T00:16:57-0400

Let us integrate dyy(y2+1):\int\frac{dy}{y(y^2 + 1)}:

dyy(y2+1)=(1yyy2+1)dy=lny12(d(y2+1)y2+1)=lny12ln(y2+1)+C.\int\frac{dy}{y(y^2 + 1)}=\int(\frac{1}{y}-\frac{y}{y^2+1})dy =\ln|y|-\frac{1}{2}\int(\frac{d(y^2+1)}{y^2+1}) \\=\ln|y|-\frac{1}{2}\ln(y^2+1)+C.


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