Answer to Question #243851 in Calculus for MINU

Question #243851

Let f(x)=−6x2+3x+10,find the slope of parabola f(x)

Expert's answer

"f(x)=-6x^2+3x+10"

"f'(x)=(-6x^2+3x+10)'=-12x+3"

"slope=m=f'(x_0)=-12x_0+3"

The slope of parabola "f(x)" at "x=x_0" is "-12x_0+3."

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