Question

Let f(x)=−6x2+3x+10,find the slope of parabola f(x)

Answer 1

$f(x)=-6x^2+3x+10$

$$f'(x)=(-6x^2+3x+10)'=-12x+3$$

$$slope=m=f'(x_0)=-12x_0+3$$

The slope of parabola $f(x)$ at $x=x_0$ is $-12x_0+3.$