length of the curve,
L=∫t1t2(dxdt)2+(dydt)2dtL=\int_{t_1}^{t_2}\sqrt{(\frac{dx}{dt})^2+(\frac{dy}{dt})^2}dtL=∫t1t2(dtdx)2+(dtdy)2dt
by using above formula, we get
L=∫t1t2(1)2+(0)2dt=∫t1t2dt=t2−t1L=\int_{t_1}^{t_2}\sqrt{(1)^2+(0)^2}dt\\ =\int_{t_1}^{t_2}dt\\ =t_2-t_1L=∫t1t2(1)2+(0)2dt=∫t1t2dt=t2−t1
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