1.Find the second and third derivatives in the simplest form of
y=x5-3x2-2x+5
2. Find by implicit differentiation of
z2-3zy+y2=6z-2y
Q1. Given function y=x5−3x2−2x+5y=x^5-3x^2-2x+5\\y=x5−3x2−2x+5
y′=dydx=5x4−6x−2y′′=d2ydx2=20x3−6x−2y′′′=d3ydx3=60x2−6y'=\frac{dy}{dx}=5x^4-6x-2\\ y''=\frac{d^2y}{dx^2}=20x^3-6x-2\\ y'''=\frac{d^3y}{dx^3}=60x^2-6y′=dxdy=5x4−6x−2y′′=dx2d2y=20x3−6x−2y′′′=dx3d3y=60x2−6
Q2. Given function z2−3zy+y2=6z−2yz^2-3zy+y^2=6z-2yz2−3zy+y2=6z−2y
2zdydz−3ydydz−3z+2y=6dydz−2⇒(2z−3y−6)dydz=3z−2y−2⇒dydz=(3z−2y−2)(2z−3y−6)2z\frac{dy}{dz}-3y\frac{dy}{dz}-3z+2y=6\frac{dy}{dz}-2\\ \Rightarrow (2z-3y-6)\frac{dy}{dz}=3z-2y-2\\ \Rightarrow \frac{dy}{dz}=\frac{(3z-2y-2)}{(2z-3y-6)}2zdzdy−3ydzdy−3z+2y=6dzdy−2⇒(2z−3y−6)dzdy=3z−2y−2⇒dzdy=(2z−3y−6)(3z−2y−2)
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