Solution;
One possible way ;
If you let;
f(x)=xf(x)=\sqrt{x}f(x)=x
g(x)=x2+xg(x)=\sqrt{x^2+x}g(x)=x2+x
h(x)=1xh(x)=\frac1xh(x)=x1
First,obtain g of f(x);
gof=g(f(x))=(f(x))2+f(x)=(x)2+x=x+xg o f=g(f(x))=\sqrt{(f(x))^2+f(x)}=\sqrt{(\sqrt{x})^2+\sqrt{x}}=\sqrt{x+\sqrt{x}}gof=g(f(x))=(f(x))2+f(x)=(x)2+x=x+x
Now we plug g(f(x)) into h(x);
F(x)=h(gof)=h(g(f(x)))F(x)=h (gof)=h(g(f(x)))F(x)=h(gof)=h(g(f(x)))
F(x)=1g(f(x))F(x)=\frac{1}{g(f(x))}F(x)=g(f(x))1 =1x+x\frac{1}{\sqrt{x+\sqrt{x}}}x+x1
Hence the expression of the function is three functions could be expressed as;
f(x)=xf(x)=\sqrt{x}f(x)=x ,g(x)=x2+xg(x)=\sqrt{x^2+x}g(x)=x2+x , h(x)=1xh(x)=\frac1xh(x)=x1 ,F(x)=hF(x)=hF(x)=h o ggg o fff
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