Answer to Question #235391 in Calculus for Philasande

Question

Evaluate the integral x / x+1 dx 

Answer 1

$$\int \dfrac{x}{x+1}dx=\int \dfrac{x+1-1}{x+1}dx=\int(1-\dfrac{1}{x+1})dx$$

$$=x-\ln|x+1|+C$$