Question

f(x) = 3(x-1) (x+2) / (x-4) (x+2)

a) state vertical asymptotes

b) state the roots:

Answer 1

$\frac{3(x-1) (x+2)}{ (x-4) (x+2)}=\frac{3(x-1)}{ (x-4)}\\ a) x+4=0=>x=-4\\ x=-4\, \text{is the vertical asymptotes.}\\ b) 3(x-1)=0=>x=1\\ x=1\,\text{is the root of the given function.}$