Unit 1 Test Review
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"y=f(x)=3x+\\frac{4}{5}\\\\\nSince, \\space 3x=y-\\frac{4}{5}\\\\\nx=\\frac{y}{3}-\\frac{4}{15}\\\\\nTherefore, \\space f^{-1}(y)=\\frac{y}{3}-\\frac{4}{15}"
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