Unit 1 Test Review
(show step by step)
y=f(x)=3x+45Since, 3x=y−45x=y3−415Therefore, f−1(y)=y3−415y=f(x)=3x+\frac{4}{5}\\ Since, \space 3x=y-\frac{4}{5}\\ x=\frac{y}{3}-\frac{4}{15}\\ Therefore, \space f^{-1}(y)=\frac{y}{3}-\frac{4}{15}y=f(x)=3x+54Since, 3x=y−54x=3y−154Therefore, f−1(y)=3y−154
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments