Question #234834

Use first principle method/definition method to obtain the derivative f(x) = 2 – x


1
Expert's answer
2021-09-12T23:51:31-0400
f(x)=limh0f(x+h)f(x)hf'(x)=\lim\limits_{h\to 0}\dfrac{f(x+h)-f(x)}{h}

=limh02(x+h)(2x)h=\lim\limits_{h\to 0}\dfrac{2-(x+h)-(2-x)}{h}


=limh0hh=2=\lim\limits_{h\to 0}\dfrac{-h}{h}=-2

f(x)=(2x)=1,xRf'(x)=(2-x)'=-1, x\in \R


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