Differentiate the following with respect to x.
b) f(x) = ln 2x . sin3 (x2 – 3)
Let us differentiate the function "f(x) = \\ln 2x \\cdot \\sin 3 (x^2 \u2013 3)" with respect to x using the product rule "(h(x)g(x))'=h'(x)g(x)+h(x)g'(x)" and the chain rule "h(g(x))'=h'(g(x))\\cdot g'(x):"
"f'(x) = \\frac{1}{2x}\\cdot 2 \\cdot \\sin 3 (x^2 \u2013 3)+\\ln 2x \\cdot \\cos 3 (x^2 \u2013 3)\\cdot 3\\cdot 2x\\\\\n=\\frac{ \\sin 3 (x^2 \u2013 3)}{x}+6x\\cdot\\ln 2x \\cdot \\cos 3 (x^2 \u2013 3)."
Comments
Leave a comment