Question

if a= 2x^2i-3yzj+xz^2k then div a is ?

Answer 1

$a = 2x^2i-3yzj+xz^2k \\diva= \nabla . F \\= \frac{\partial}{\partial x}2x^2 - \frac{\partial}{\partial y} 3yz + \frac{\partial}{\partial z}xz^2 \\4x-3z+2xz$