Answer to Question #229606 in Calculus for Okokok

Question #229606

if a= 2x^2i-3yzj+xz^2k then div a is ?

Expert's answer

"a = 2x^2i-3yzj+xz^2k\n\\\\diva= \\nabla . F\n\\\\= \\frac{\\partial}{\\partial x}2x^2 - \\frac{\\partial}{\\partial y} 3yz + \\frac{\\partial}{\\partial z}xz^2\n\\\\4x-3z+2xz"

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