Differentiate f(x) = 5𝑥³+7𝑥 2𝑥²−4𝑥+5 using quotient rule.
"f'(x)=\\left(\\frac{5x^3+7x}{2x^2-4x+5}\\right)'=\\\\ {}=\\frac{(5x^3+7x)'(2x^2-4x+5)-(5x^3+7x)(2x^2-4x+5)'}{(2x^2-4x+5)^2}=\\\\ {}=\\frac{(15x^2+7)(2x^2-4x+5)-(5x^3+7x)(4x-4)}{(2x^2-4x+5)^2}=\\\\ {}=\\frac{10x^4-40x^3+61x^2+35}{(2x^2-4x+5)^2}"
Comments
Leave a comment