Question

f(x) = 2x⁴ + 8x³ - 16x² - 96x + 100

f'(x)=?

Answer 1

Let $f(x) = 2x^4 + 8x^3 - 16x^2 - 96x + 100.$ Taking into account that $(x^n)'=nx^{n-1},$ we conclude that $f'(x) = 8x^3 + 24x^2 - 32x - 96.$