f(x) = 2x⁴ + 8x³ - 16x² - 96x + 100
f'(x)=?
Let "f(x) = 2x^4 + 8x^3 - 16x^2 - 96x + 100." Taking into account that "(x^n)'=nx^{n-1}," we conclude that "f'(x) = 8x^3 + 24x^2 - 32x - 96."
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