Question #223113

Find the general solution of these differential equations.

1) dy/dx = x/y2 2)dy/dx = x+2 / y


1
Expert's answer
2021-09-13T00:26:05-0400

1.dydx=xy2Cross-multiplying we have,y2dy=(x+2)dxIntegrating both sides we havey33=x22+c2.dydx=x+2y=ydy=(x+2)dx=y22=x22+2x+c1. \frac{dy}{dx} = \frac{x}{y^2}\\ \text{Cross-multiplying we have,}\\ y^2dy= (x+2)dx\\ \text{Integrating both sides we have}\\ \frac{y^3}{3}=\frac{x^2}{2}+c\\ 2. \frac{dy}{dx}=\frac{x+2}{y}\\ =ydy = (x+2)dx\\ =\frac{y^2}{2}=\frac{x^2}{2}+2x+c


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