Question #2208
Estimate the arc length of r(t) = (cos^2 t, sin 3t), t element of [0, pi] using trapezoidal rule with n = 6.
Expert's answer
Divide the interval in n parts. Find distance between every pair of two nearest points.
t 0 π/6 π/3 π/2 2π/3 5π/6 π
x=cos2t 1 3/4 1/4 0 1/4 3/4 1
y=sin3t 0 1 0 -1 0 1 0
d=√((xk-xk-1)2+(yk - yk-1 )2) - √17/4 √5/2 √17/4 √17/4 √5/2 √17/4
The arc length is the sum of smaller parts:
L = √17/4 + √5/2 + √17/4 + √17/4 + √5/2 + √17/4 = √17 + √5 ≈ 6.3592
t 0 π/6 π/3 π/2 2π/3 5π/6 π
x=cos2t 1 3/4 1/4 0 1/4 3/4 1
y=sin3t 0 1 0 -1 0 1 0
d=√((xk-xk-1)2+(yk - yk-1 )2) - √17/4 √5/2 √17/4 √17/4 √5/2 √17/4
The arc length is the sum of smaller parts:
L = √17/4 + √5/2 + √17/4 + √17/4 + √5/2 + √17/4 = √17 + √5 ≈ 6.3592
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#340153 on Dec 2023
#340153 on Dec 2023