Question #220254
“Count Every Particle” is a game conducted by the teachers and students to generate funds for the victims of Typhoon. The game was, the participant will buy a ticket so that they have chance to guess the exact number of particles of the sand that is placed in a vase. The following hints were given:
(1) It is assumed that the volume of every particle is 6.4π x 10^-12 cm^3.
(2) The height of the vase is 32 cm; and
(3) The equation of the curve that the vase made of is given by y=x^2 - 6 wit domain x≥ -2.
To win this game, calculate the exact number of particles that can be placed in the vase.
1
Expert's answer
2021-07-27T07:34:26-0400

(1) V1=6.4π×1012V_1=6.4\pi\times10^{-12} cm3


(2) h=32h=32 cm


(3) y=x26y=x^2-6


y(2)=(2)26=2y(-2)=(-2)^2-6=-2

2+32=30-2+32=30

x26=30=>x=±6x^2-6=30=>x=\pm6

x=y+6x=-\sqrt{y+6}

V=π230(y+6)2dy=π[y22+6y]302=640π(cm3)V=\pi\displaystyle\int_{-2}^{30}(-\sqrt{y+6})^2dy=\pi\bigg[\dfrac{y^2}{2}+6y\bigg]\begin{matrix} 30 \\ -2 \end{matrix}=640\pi(cm^3)


N=VV1=640π cm36.4π×1012 cm3=1014N=\dfrac{V}{V_1}=\dfrac{640\pi\ cm^3}{6.4\pi\times10^{-12}\ cm^3}=10^{14}

The exact number of particles that can be placed in the vase is 1014.10^{14}.




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