Question #213990

A cobb douglas production function for a new company is given by F(x,y)=50x3/5y2/5. Where x represents the units of labor and y represents the units of capital. Suppose the units of labor and the capital cost is $200 and $100 each respectively and the budget constraint is $30,000. Find the maximum production level for this manufacturer.


1
Expert's answer
2021-07-09T11:16:27-0400
200x+100y=30000=>y=3002x,x,y0200x+100y=30000=>y=300-2x, x, y\geq 0

Then


F=F(x)=50x3/5(3002x)2/5,0x150F=F(x)=50x^{3/5}(300-2x)^{2/5}, 0\leq x\leq 150

Find the first derivative with respect to xx


F(x)=(50x3/5(3002x)2/5)F'(x)=(50x^{3/5}(300-2x)^{2/5})'

=50(35x2/5(3002x)2/525(2)x3/5(3002x)3/5)=50(\dfrac{3}{5}x^{-2/5}(300-2x)^{2/5}-\dfrac{2}{5}(2)x^{3/5}(300-2x)^{-3/5})

=10x2/5(3002x)3/5(3(3002x)4x)=10x^{-2/5}(300-2x)^{-3/5}(3(300-2x)-4x)

=100x2/5(3002x)3/5(90x)=100x^{-2/5}(300-2x)^{-3/5}(90-x)


F(x)=0=>100x2/5(3002x)3/5(90x)=0F'(x)=0=>100x^{-2/5}(300-2x)^{-3/5}(90-x)=0

=>x=90=>x=90

Critical numbers: 0,90,1500, 90, 150

F(0)=0F(0)=0


F(150)=0F(150)=0



F(90)=50(90)3/5(30090)2/5=F(90)=50(90)^{3/5}(300-90)^{2/5}=

=1500(1323)1/56315.43=1500(1323)^{1/5}\approx6315.43

The maximum production level is $6315.43 and occurs when x=90 units of labor and y=120 units of capital.



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