how many terms of the arithmetic series 10 + 8 + 6 +... will make the sum 24?
This is the arithmetic sequence with a1=10,d=−2.a_1=10, d=-2.a1=10,d=−2.
Sn=n2(2a1+(n−1)d)S_n=\frac{n}{2}(2a_1+(n-1)d)Sn=2n(2a1+(n−1)d)
n2(20−2(n−1))=24\frac{n}{2}(20-2(n-1))=242n(20−2(n−1))=24
n2−11n+24=0n^2-11n+24=0n2−11n+24=0
n=3n=3n=3
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