lim ( tan x) = ∞
x→π/2
True or false with full explanation
Taking into account that "\\lim\\limits_{x\\to\\frac{\\pi}{2}}\\sin x=\\sin\\frac{\\pi}{2}=1" and "\\lim\\limits_{x\\to\\frac{\\pi}{2}}\\cos x=\\cos\\frac{\\pi}{2}=0," we conclude that "\\lim\\limits_{x\\to\\frac{\\pi}{2}}\\tan x=\\lim\\limits_{x\\to\\frac{\\pi}{2}}\\frac{\\sin x}{\\cos x}=|\\frac{1}{0}|=\\infty."
Answer: true
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