Answer to Question #206896 in Calculus for Haris Ghafoor

Question

Find f_x(x,y), f xy(x,y), f x(1,3), and f y(-2,4) for the given function.

Answer 1

$𝑧 = 𝑓(𝑥, 𝑦) = 3𝑥^3𝑦^2 − 𝑥^2𝑦^3 + 4𝑥 + 9$

$f_x(x, y)=9x^2y^2-2xy^3+4$

$f_y(x, y)=6x^3y-3x^2y^2$

$f_{xx}(x, y)=18xy^2-2y^3$

$f_{xy}(x, y)=18x^2y-6xy^2=f_{yx}(x, y)$

$f_{yy}(x, y)=6x^3-6x^2y$

$f_x(1, 3)=9(1)^2(3)^2-2(1)(3)^3+4=31$

$f_y(-2, 4)=6(-2)^3(4)-3(-2)^2(4)^2=-384$