Answer to Question #206547 in Calculus for lindz

Question

derive a reduction formula e^(mx)/x^ndx

Answer 1

u=e^mx

du=me^mxdx

dv=x^-ndx

v=x^1-n/(1-n)

$\int \frac{e^mx}{x^n}dx=\frac{e^{mx}x^{1-n}}{1-n}-m\int \frac{x^{1-n}e^{mx}}{1-n}dx$