Find fx(x,y), fy(x,y), fx(1,3), and fy(-2,4) for the given function. If
π§ = π(π₯, π¦) = 3π₯ΰ¬·π¦ΰ¬Ά β π₯ΰ¬Άπ¦ΰ¬· + 4π₯ + 9
Given f(x,y) = 3x2y - xy2 + 4x + 9
Now fx(x,y) = (d/dx)(3x2y - xy2 + 4x + 9)
= 6xy - y2 + 4
Now fx(1,3) = 6*1*3 - 32 + 4 = 13
Now fy(x,y) = (d/dy)(3x2y - xy2 + 4x + 9)
= 3x2 - 2xy
Now fy(-2,4) = 3(-2)2 - 2(-2)(4) = 28
Comments