Question

The velocity ,vms-1,of a fairground ride t seconds after it begins is given by v = (3e-t + 7)sin t

What is the acceleration of the ride 2 seconds after it begins?

Answer 1

$$v(t)=(3e^{-t}+7)\sin t$$

$$a(t)=v'(t)=-3e^{-t}\sin t+(3e^{-t}+7)\cos t$$

$$a(2)=-3e^{-2}\sin (2)+(3e^{-2}+7)\cos (2) (m\cdot s^{-2})$$

$$\approx-3.451166\ (m\cdot s^{-2})$$