What is the area enclosed by the graph of
y = x2 + x – 2
below the x-axis?
we have equation
"y = x^2 + x \u2013 2"
we have to get the area below the x-axis ,see the graph below to get better idea
this part of parabola is required area
so we have to solve the integral "\\int_{-1}^{2}x^2-x+2 dx\n\\\\"
"=[\\frac{x^3}{3}-\\frac{x^2}{2}+2x]_{-1}^{2}=\\frac{-9}{2}=-4.5"
taking mod the answer is 4.5 unit"^2"
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