The region above the x-axis and below the curve 𝑦 = 𝑒 −𝑥 𝑓𝑜𝑟 0 ≤ 𝑥 ≤ ∞ is rotated around the x-axis. Find the volume of the solid generated.
V=∣∫0∞π(e−x)2dx∣=∣π2e2x∣0∞∣=π/2V=|\int^{\infin}_0\pi(e^{-x})^2dx|=|\frac{\pi}{2e^{2x}}|^{\infin}_0|=\pi/2V=∣∫0∞π(e−x)2dx∣=∣2e2xπ∣0∞∣=π/2
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