What is the derivative of cos4x
Solution:
Let y=cos4xy=\cos 4xy=cos4x
Differentiating both sides w.r.t xxx,
y′=−sin4x×(4x)′=−4sin4xy'=-\sin 4x \times (4x)' =-4\sin 4xy′=−sin4x×(4x)′=−4sin4x
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