Answer to Question #198249 in Calculus for RITESH TAK

Question #198249

Differentiate, y=ln(xlnx)


1
Expert's answer
2021-05-25T16:20:34-0400

y=ln(xlnx)y=ln(xlnx)


Differentiate w.r.t. x-


dydx=1xlnx(lnx+x(1x))\dfrac{dy}{dx}=\dfrac{1}{xlnx}(lnx+x(\dfrac{1}{x}))


=lnx+1xlnx=\dfrac{lnx+1}{xlnx}


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