Answer to Question #19589 in Calculus for Oge Odita
find the exact value of the following definite integral of the antiderivative on 3 and 0 of (1/x^2 +3) dx
1
2012-11-28T08:51:04-0500
int^0_3 (1/x^2 +3) dx = (-1/x+ 3x)|^0_3 = infinity
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