Question #1938

Use the definition of e, and numerical approximations as y approaches 0 from the left, and y approaches 0 from the right.

(b) Use a calculator to estimate the values of the limits given below, correct to two decimal places.
lim (y -> 0) (2.7[sup]y[/sup] - 1)/ y and lim (y -> 0) (2.8[sup]y[/sup] - 1)/ y

____ < 1 < _______

What can you conclude about the value of e?

________ < e < _________

Expert's answer

Question #1838 Use the definition of ee, and numerical approximations as y approaches 0 from the left, and y approaches 0 from the right.

(b) Use a calculator to estimate the values of the limits given below, correct to two decimal places. limy0(2.7y1)/y\lim_{y\to 0}(2.7^y -1) / y and limy0(2.8y1)/y\lim_{y\to 0}(2.8^y -1) / y What can you conclude about the value of e?

Solution. The first question is unclear. For the next use if a>0a > 0 then limx0ax1x=lna\lim_{x\to 0}\frac{a^x - 1}{x} = \ln a. Hence limy0(2.7y1)/y=ln2.70.99\lim_{y\to 0}(2.7^y -1) / y = \ln 2.7\approx 0.99 and limy0(2.8y1)/y=log2.81.03\lim_{y\to 0}(2.8^y -1) / y = \log 2.8\approx 1.03. Hence 2.7<e<2.82.7 < e < 2.8.

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