what is the area under the curve y(x)= 3e^-5x from x = 1 to x= ∞
A=∫1∞3e−5xdx=−35e−5x∣x=1x=∞=35e−5.A=\int_1^\infin 3e^{-5x}dx=-\frac{3}{5}e^{-5x}|_{x=1}^{x=\infin}=\frac{3}{5}e^{-5}.A=∫1∞3e−5xdx=−53e−5x∣x=1x=∞=53e−5.
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